ΔG??= ΔHreaction??- TΔSsystem?
Calculating ΔG?
ΔG??from ΔH??and ΔS??valuesCalculate the free energy change for the following reaction:
2NaHCO3?(s)?→ Na2CO3?(s) + H2O (l) + CO2?(g)
ΔH??= +135?kJ mol-1? ? ? ??ΔS??= +344?J K-1?mol-1
Answer
Step 1:?Convert the entropy value in kilojoules
ΔS??= +344 J K-1?mol-1??÷ 1000 = +0.344 kJ K-1?mol-1
Step 2:?Substitute the terms into the Gibbs Equation
ΔG??= ΔHreaction??- TΔSsystem?
= +135 - (298 x 0.344)
=?+32.49 kJ mol-1
The temperature is 298 K since standard values are quoted in the question
ΔG??from other ΔG??valuesWhat is the standard free energy change, ΔG?, for the following reaction?
C2H5OH(l) + 3O2(g)?→?2CO2(g) + 3H2O(g)

Answer
ΔG??= ΣΔGproducts??- ΣΔGreactants?
ΔG??= [(2 x CO2?) + (3 x H2O )] - [(C2H5OH) + (3 x O2)]
ΔG??= [(2 x -394?) + (3 x -229 )] - [-175 + 0]
ΔG??=?-1300 kJ?mol-1
The idea of free energy is what's 'leftover' to do useful work when you've carried out the reaction. The enthalpy change is the difference between the energy you put in to break the chemical bonds and the energy out when making new bonds; the entropy change is the 'cost' of carrying our the reaction, so free energy is what is you are left with!
轉載自savemyexams
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