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Where:

Gravitational potential energy increases as a satellite leaves the surface of the Moon
A spacecraft of mass 300 kg leaves the surface of Mars to an altitude of 700 km. Calculate the work done by the spacecraft. The radius of Mars = 3400 km,?Mass of Mars = 6.40 × 1023?kg
Work Done on a Charge
Where:

Work is done when moving a point charge away from another charge
The potentials at points?R?and?S?due to the +7.0 nC charge are 675 V and 850 V respectively.

Calculate how much work is done when a +3.0 nC charge is moved from?R?to?S.
Step 1: Write down the known quantities
Step 2: Write down the work done equation
W?=?q ×?ΔV
Step 3: Substitute in the values into the equation
W = (3.0 × 10-9) × (850 - 675) = 5.3 × 10-7?J
Make sure to not confuse the ΔG.P.E equation with ΔG.P.E = mgΔh, they look similar but refer to quite different situations.
The more familiar equation is only relevant for an object lifted in a uniform gravitational field, meaning very close to the Earth’s surface, where we can model the field as uniform.
The new equation for G.P.E does not include g. The gravitational field strength, which is different on different planets, does not remain constant as the distance from the surface increases. Gravitational field strength falls away according to the inverse square law.
Remember that?q?in the work done equation is the charge that is being moved, whilst?Q?is the charge which is producing the potential. Make sure not to get these two mixed up. It is common for both to be given in the question, as in our worked example. You are expected to choose the correct one.
轉載自savemyexams
以上就是關于【IB DP Physics: HL復習筆記10.2.1 Potential & Potential Energy】的解答,如需了解學校/賽事/課程動態,可至翰林教育官網獲取更多信息。
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