KCl (s) + aq → KCl?(aq)
OR
KCl?(s) + aq → K+?(aq) + Cl-?(aq)
Mg2+(g) + aq → Mg2+(aq)

The polar water molecules will form ion-dipole bonds with the ions in solution causing the ions to become hydrated

The relationship between lattice enthalpy, hydration enthalpies and enthalpy of solution
Enthalpy of solution = reverse lattice enthalpy* + hydration enthalpy
*To be consistent with lattice?formation?enthalpy
ΔHhyd??= ΔHlatt??+ ΔHsol?
Constructing an energy cycle for KClCalculate the enthalpy of hydration of the chloride ion given the following data:
ΔHlatt??[KCl] = -711 kJ mol-1
ΔHsol??[KCl] = +26 kJ mol-1
ΔHhyd??[K+] = -322 kJ mol-1
Answer
Step 1:?Draw the energy cycle and make ΔHhyd[Cl-] the subject of the formula:

Step 2:?Substitute the values to find ΔHhyd??[Cl-]
ΔHhyd??[Cl-]?? = (-711) + (+26) - (-322) = -363 kJ mol-1
Alternative Diagram
Energy level diagram:


Constructing an energy cycle and energy level diagram of MgCl2
Construct an energy cycle to calculate the ΔHhyd?of magnesium ions in magnesium chloride, given the following data:
ΔHlatt?[MgCl2] = -2592 kJ mol-1
ΔHsol?[MgCl2] = -55 kJ mol-1
ΔHhyd?[Cl-] = -363 kJ mol-1
Answer
Step 1:?Draw an energy cycle:
Step 2:?Substitute the values to find ΔHhyd??[Mg2+]
ΔHhyd?[Mg2+]? = (-2592) + (-55) - (2 x -363) = -1921 kJ mol-1
Alternative route to find ΔHhyd?[Mg2+]

It doesn't matter whether you use Hess cycles or Born-Haber style cycles to solve these problems as long as the information is correctly labelled and the direction of the arrows matches the definitions.Exam problems in this topic often show diagrams with missing labels which you have to complete and find unknown values.The key to success in energy cycle calculations is not to panic, but have a careful step-by-step approach, show your workings and use brackets to separate mathematical operations from the enthalpy changes.

The lattice energies get less exothermic as the ionic radius of the ions increases
轉載自savemyexams
以上就是關于【Edexcel A Level Chemistry:復習筆記5.3.4 Enthalpy of Solution】的解答,如需了解學校/賽事/課程動態,可至翰林教育官網獲取更多信息。
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