



When hydrogen ions are added to the solution the pH of the solution would decrease; However, the ethanoate ions in the buffer solution react with the hydrogen ions to prevent this and keep the pH constant
OH-?(aq) + H+??(aq) → H2O (l)
CH3COOH (aq) → H+?(aq) + CH3COO-?(aq)

When hydroxide ions are added to the solution, the hydrogen ions react with them to form water; The decrease in hydrogen ions would mean that the pH would increase however the equilibrium moves to the right to replace the removed hydrogen ions and keep the pH constant



Calculate the pH of a buffer solution containing 0.305 mol dm-3?of ethanoic acid and 0.520 mol dm-3?sodium ethanoate.
The?Ka?of ethanoic acid? = 1.74 × 10-5?mol dm-3?at 298 K
Answer
Ethanoic acid is a weak acid that ionises as follows:
CH3COOH (aq) ? H+?(aq) + CH3COO-?(aq)
Step 1:?Write down the equilibrium expression to find?Ka

Step 2:?Rearrange the equation to find [H+]

Step 3:?Substitute the values into the expression

???= 1.02 x 10-5?mol dm-3
Step 4:?Calculate the pH
???pH = - log [H+]
???= -log 1.02 x 10-5
???= 4.99
???? ?[H+(aq)] = 1.00 x 10-5?mol dm-3
? ? 
???? ?Ka?= 1.74 x 10-5?mol dm-3
? ? 
? ? 
? ? 
CO2?(g) + H2O (l) ? H+?(aq) + HCO3-?(aq)
H+?(aq) + HCO3-?(aq) ? CO2?(g) + H2O (l)
CO2 (g) + H2O (l) ? H+ (aq) + HCO3- (aq)
轉載自savemyexams
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