The black body radiation curve for different temperatures peaks at a wavelength which is inversely proportional to the temperature


The intensity-wavelength graph shows how thermodynamic temperature links to the peak wavelength for four different stars
λmaxT = 2.9 × 10?3?m K
Table to compare surface temperature and star colour

The spectrum of the star Rigel in the constellation of Orion peaks at a wavelength of 263 nm, while the spectrum of the star Betelgeuse peaks at a wavelength of 828 nm.Which of these two stars is cooler, Betelgeuse or Rigel?
Step 1:?Write down Wien’s displacement law
λmaxT = 2.9 × 10-3?m K
Step 2:?Rearrange for temperature T

Step 3:?Calculate the surface temperature of each star


Step 4:?Write a concluding sentence
Betelgeuse has a surface temperature of 3500 K, therefore, it is much cooler than Rigel

The Orion Constellation; cooler stars, such as Betelguese, appear red or yellow, while hotter stars, such as Rigel, appear white or blue
Note that the temperature used in Wien’s Law is in?Kelvin?(K). Remember to convert from?oC if the temperature is given in degrees in the question before using the Wien’s Law equation.
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