F = BQv sinθ

The force on an isolated moving charge is perpendicular to its motion and the magnetic field B
F = BQv
An electron is moving at 5.3 × 107?m s-1 in a uniform magnetic field of flux density 0.2 T.Calculate the force on the electron when it is moving at 30° to the field, and state the factor it increases by compared to when it travels perpendicular to the field.
Step 1:?Write out the known quantities
Speed of the electron, v = 5.3 × 107?m s-1
Charge of an electron, Q = 1.60 × 10-19?C
Magnetic flux density, B = 0.2 T
Angle between electron and magnetic field, θ = 30°
Step 2: Write down the equation for the magnetic force on an isolated particle
F = BQv sinθ
Step 3: Substitute in values, and calculate the force on the electron at 30°
F = (0.2) × (1.60 × 10-19) × (5.3 × 107) × sin(30) = 8.5 × 10-13?N
Step 4: Calculate the electron force when travelling perpendicular to the field
F = BQv = (0.2) × (1.60 × 10-19) × (5.3 × 107) = 1.696 × 10-12 N
Step 5: Calculate the ratio of the perpendicular force to the force at 30°

Therefore, the force on the electron is twice as strong when it is moving perpendicular to the field than when it is moving at 30°?to the field
Remember not to mix this up with F = BIL!
轉載自savemyexams
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