• A charged particle in an electric field will experience a force on it that will cause it to move
• If a charged particle remains still in a uniform electric field, it will move parallel to the electric field lines (along or against the field lines depending on its charge)
• If a charged particle is in?motion?through a uniform electric field (e.g. between two charged parallel plates), it will experience a constant electric force and travel in a?parabolic trajectory

The parabolic path of charged particles in a uniform electric field

• The direction of the parabola will depend on the charge of the particle
  • A?positive?charge will be deflected towards the?negative?plate
  • A?negative?charge will be deflected towards the?positive?plate
• The force on the particle is the same at all points and is always in the same direction
• Note:?an uncharged particle, such as a neutron experiences no force in an electric field and will therefore travel straight through the plates undeflected
• The amount of deflection depends on the following properties of the particles:
  • Mass?– the greater the mass, the smaller the deflection and vice versa
  • Charge?– the greater the magnitude of the charge of the particle, the greater the deflection and vice versa
  • Speed?– the greater the speed of the particle, the smaller the deflection and vice versa

Step 1:???????????

Compare the charge of the boron nucleus to the proton

• • Boron has 5 protons, meaning it has a charge 5 × greater than the proton
  • The force on boron will therefore be 5 × greater than on the proton

Step 2:???????????

Compare the mass of the boron nucleus to the proton

• • The boron nucleus has a mass of 11 nucleons meaning its mass is 11 × greater than the proton
  • The boron nucleus will therefore be less deflected than the proton

Step 3:???????????

Draw the trajectory of the boron nucleus

• • Since the mass comparison is much greater than the charge comparison, the boron nucleus will be?much less deflected?than the proton
  • The nucleus is positively charged since the neutrons in the nucleus have no charge
    • Therefore, the shape of the path will be the same as the proton