The energy stored within a material (e.g. in a spring) when it is stretched or compressed

EPE = KE
??kx2?= ??mv2
v?∝?x
A car’s shock absorbers make a ride more comfortable by using a spring that absorbs energy when the car goes over a bump. One of these springs, with a force constant of 50 kN m–1 is fixed next to a wheel and compressed a distance of 10 cm.Calculate the energy stored by the compressed spring.
Step 1: List the known values
Step 2: Write the relevant equation
EPE = ??kx2
Step 3: Substitute in the values
EPE = ? × (50 × 103) × (10 × 10–2)2?=?250 J
Work done is the area under the force-extension graph

The ultimate breaking stress is the point on the stress-strain graph of maximum stress. The breaking point is where the material fractures
The graph shows the behaviour of a sample of a metal when it is stretched until it starts to undergo plastic deformation.
Calculate the total work done in stretching the sample from zero to an extension of 13.5 mm.Simplify the calculation by treating the curve XY as a straight line.


A spring is extended with varying forces; the graph below shows the results.
Calculate the energy stored in the spring when the extension is 40 mm.

轉載自savemyexams
以上就是關于【IB DP Physics: SL復習筆記2.3.3 Elastic Potential Energy】的解答,如需了解學校/賽事/課程動態,可至翰林教育官網獲取更多信息。
往期文章閱讀推薦:
翰林獨家 | 經濟學競賽核心精講,一冊打通NEC/IEO/USAEBO!
2026 AMC10/12美國數學競賽新賽季!【翰林教育 × 清華大學出版社】獨家教材全面發售!

? 2026. All Rights Reserved. 滬ICP備2023009024號-1