

Three resistors connected in series. The total voltage is the sum of the individual voltages, and the total resistance is the sum of the three individual resistances
The combined resistance?R?in the following series circuit is 60 Ω.What is the resistance value of?R2?
A? ? ?100 Ω? ? ? ? ? ? ? ?B? ? ?30 Ω? ? ? ? ? ? ? ?C? ? ?20 Ω? ? ? ? ? ? ? ?D? ? ?40 Ω
ANSWER:? C
Step 1: Write down the equation for the combined resistance in series
R?=?R1?+?R2?+?R3
Step 2: Substitute the values for total resistance?R?and the other resistors
60 Ω = 30 Ω +?R2?+ 10 Ω
Step 3: Rearrange for?R2
R2?= 60 Ω – 30 Ω – 10 Ω =?20 Ω
Dennis sets up a series circuit as shown below.
The cell supplies a current of 2 A to the circuit, and the fixed resistor has a resistance of 4 Ω.
(a) How much current flows through the fixed resistor?
(b) What is the reading on the voltmeter?
Part (a)
Step 1: Recall that current is conserved in a series circuit
Part (b)
Step 1: List the known quantities
Step 2: State the equation linking potential difference, resistance and current
V = IR
Step 3: Substitute the known values into the equation and calculate the potential difference
V =?2 × 4 = 8 V
轉載自savemyexam
以上就是關于【Edexcel IGCSE Physics 復習筆記 2.2.3 Resistors in Series】的解答,如需了解學校/賽事/課程動態,可至翰林教育官網獲取更多信息。
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