


An electric motor has an efficiency of 35 %. It lifts a 7.2 kg load through a height of 5 m in 3 s.Calculate the power of the motor.
Step 1: Write down the efficiency equation

Step 2: Rearrange for the power input??
Step 3: Calculate the power out
Gravitational potential energy = mgh = 7.2 × 9.81 × 5 = 353.16 J
Power = 353.16 ÷ 3 = 117.72 W
Step 4: Substitute values into power input equation?
Efficiency can be in a ratio or percentage format.If the question asks for efficiency as a ratio, give your answer as a fraction or decimal.If the answer is required as a percentage, remember to multiply the ratio by 100 to convert it: if the ratio = 0.25, percentage = 0.25 × 100 = 25 %
轉載自savemyexams
以上就是關于【AQA A Level Physics復習筆記4.6.3 Efficiency】的解答,如需了解學校/賽事/課程動態,可至翰林教育官網獲取更多信息。
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