
When the force is not constant, the impulse is the area under a force–time graph
Impulse?=?Force?×?Change in time

A ball of mass 3.0 kg, initially at rest, is acted on by a force F which varies with t as shown by the graph.
Calculate the velocity of the ball after 16 s.
Step 1: List the known quantities
m = 3.0 kg
u = 0 m s-1?(since it is initially at rest)
Step 2: Calculate the impulse
The impulse is the area under the graph. The graph can be split up into two right-angled triangles with a base of 8 s and a height of 4 kN

Area = impulse = 32 × 103?Ns
Step 3: Write the equation for impulse
Impulse,?I = Δp = m(v – u)
Step 4: Substitute in the values
I = mv
32 × 103?= 3.0 × v
v = (32 × 103) ÷ 3.0
v = 10666 m s–1?= 11 km s-1
Some maths tips for this section:Rate of Change
Areas

A cricket fielder moves their hands backwards when catching a cricket ball to reduce the force it will exert on their hands

The follow through action of a football kick increases the change in momentum of the ball
A tennis ball hits a racket with a change in momentum of 0.5 kg m s-1.For the different contact times, which tennis racket experiences more force from the tennis ball?

轉載自savemyexams
以上就是關于【AQA A Level Physics復習筆記4.5.4 Impulse on a Force-Time Graph】的解答,如需了解學校/賽事/課程動態,可至翰林教育官網獲取更多信息。
往期文章閱讀推薦:
MIT官方發布【2026年夏季推薦閱讀書單】!橫跨科學/人文/經濟...
全網破防!ALevel CIE數學M1疑似錯題?經濟P2難度飆升?5月6日大考考情分析必看!

? 2026. All Rights Reserved. 滬ICP備2023009024號-1