
Example of a working out what is conserved in Kaon decay. This decay must be through the weak interaction since S is not conserved
The lambda nought particle Λ0?is made up from the quarks uds.Show, in terms of the conservation of charge, strangeness, baryon number and lepton number whether the following interaction is permitted
Step 1: Determine conservation of charge
0 = –1 + 1 + 0
Charge is conserved
Step 2: Determine conservation of strangeness
Λ0?has an s quark, so must have a strangeness of –1
–1 = 0 + 0 + 0
Strangeness is not conserved
Step 3: Determine conservation of baryon number
Λ0?is a baryon since it has 3 quarks, so must have a baryon number of +1
+1 = 0 + 0 + 0
Baryon number is not conserved
Step 4: Determine conservation of lepton number
Λ0?is a baryon, so must have a lepton number of 0
0 = 0 + (–1) + 1
Lepton number is conserved
Step 5: Conclusion
Since the baryon number is not conserved, this interaction is?not permitted
The equation for β–?decay is
Using the quark model of beta decay, prove that the charge is conserved in this equation.

Note:
轉載自savemyexams
以上就是關于【AQA A Level Physics復習筆記2.3.5 Application of Conservation Laws】的解答,如需了解學校/賽事/課程動態,可至翰林教育官網獲取更多信息。
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