
The basic principle of a Born-Haber cycle

Drawing a Born-Haber cycle step 1
Na (s) → Na (g)? ? ? ? ? ?ΔHat??= +108 kJ mol?-1
?Cl2?(g) → Cl?(g)? ? ? ?ΔHat??= +121 kJ mol?-1

Drawing a Born-Haber cycle step 2 - creating the gaseous atoms
Na (g) → Na+?(g) + e–? ? ? ? ??ΔHie??= +500 kJ mol-1
Cl?(g)?+ e–?→ Cl-?(g)? ? ? ? ? ?ΔHea??= -364 kJ mol-1

Drawing a Born-Haber cycle step 3 - creating the gaseous ions
Na(s) +??Cl2?(g)?→ NaCl?(s)? ? ? ? ? ? ΔHf??= -411 kJ mol?-1
Na+(g) + Cl-(g) → NaCl?(s)? ΔHlatt?

Drawing a Born-Haber cycle step 4 - completing the cycle
Constructing a Born-Haber cycle for KClConstruct a Born-Haber Cycle which can be used to calculate the lattice energy of potassium chloride.
Answer

Constructing a Born-Haber cycle for MgOConstruct a Born-Haber Cycle which can be used to calculate the lattice energy of magnesium oxide.
Answer

When constructing Born-Haber cycles, the direction of the changes is important, but the relative size of the steps does not matter so don't worry if the steps don't correspond to the magnitude of the energy changes.You don't need to show the energy axis in a Born-Haber cycle, but you do need to show the electron(s) in the ionisation step otherwise you might lose marks in an exam.
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