Time ÷ duration of the refractory period
1 ÷ duration of the refractory period
Figure 1?shows the changes in the permeability of a section of an axon membrane to two ions that are involved in the production of an action potential. Use the information in?Figure 1?to calculate the maximum frequency of action potentials per second along the axon. Show your working.
Step 1: Determine the duration of the refractory period
From the graph: 2.75 milliseconds
Step 2: Convert this to seconds
0.00275 seconds
Step 3: Insert relevant figures into the equation
Time ÷ duration of the refractory period
1 ÷ 0.00275 = 363.63
Answer = 364 action potentials sec-1
It is very important to check the units given in the question. For example, the duration of the refractory period may be given in milliseconds but the answer must be in action potentials sec-1. 1000 milliseconds = 1 seconds!
轉載自savemyexams
以上就是關于【AQA A Level Biology復習筆記6.2.6 Maths Skill: Calculating Maximum Impulse Frequency】的解答,如需了解學校/賽事/課程動態,可至翰林教育官網獲取更多信息。
往期文章閱讀推薦:
MIT官方發布【2026年夏季推薦閱讀書單】!橫跨科學/人文/經濟...
全網破防!ALevel CIE數學M1疑似錯題?經濟P2難度飆升?5月6日大考考情分析必看!

? 2026. All Rights Reserved. 滬ICP備2023009024號-1