percentage error = (uncertainty value ÷ your measurement) x 100
In an enzyme rate reaction involving the breakdown of hydrogen peroxide by catalase, 50 cm3?of oxygen was produced, with an uncertainty value of 0.05 cm3. Calculate the percentage error of this measurement.
Percentage error = (uncertainty value ÷ your measurement) x 100
Percentage error = (0.05 ÷ 50) x 100
Percentage error = 0.001 x 100
Percentage error = 0.1%
In an enzyme rate experiment involving the breakdown of hydrogen peroxide by catalase, a student recorded that 10 cm3 of oxygen was produced in 5.245 seconds. The student measured this using a stopwatch that counted in milliseconds. Calculate the percentage error of the stopwatch measurements.
Step 1: Calculate the uncertainty value
The stopwatch can measure to the nearest millisecond (0.001?second)
This means the actual time taken could be up to?0.0005?seconds?shorter?or?longer?than this
This means stopwatch measurements have an uncertainty value of?± 0.0005 s
Step 2: Calculate the percentage error?of the student’s measurement of 5.245 seconds
Percentage error = (uncertainty value ÷ your measurement) x 100
Percentage error = (0.0005 ÷ 5.245) x 100
Percentage error = 0.000095 x 100
Percentage error = 0.0095% or 0.01%
轉(zhuǎn)載自savemyexams
以上就是關(guān)于【AQA A Level Biology復(fù)習(xí)筆記1.4.14 Practical Skill: Controlling Variables & Calculating Uncertainty】的解答,如需了解學(xué)校/賽事/課程動態(tài),可至翰林教育官網(wǎng)獲取更多信息。
往期文章閱讀推薦:
MIT官方發(fā)布【2026年夏季推薦閱讀書單】!橫跨科學(xué)/人文/經(jīng)濟(jì)...
全網(wǎng)破防!ALevel CIE數(shù)學(xué)M1疑似錯題?經(jīng)濟(jì)P2難度飆升?5月6日大考考情分析必看!

? 2026. All Rights Reserved. 滬ICP備2023009024號-1