• The?magnetic flux linkage?is a quantity commonly used for solenoids which are made of?N?turns of wire
• Magnetic flux linkage is defined as:

The product of the magnetic flux and the number of turns

• It is calculated using the equation:

ΦN = BAN

• Where:
  • Φ =?magnetic flux?(Wb)
  • N = number of turns of the coil
  • B = magnetic flux density (T)
  • A = cross-sectional area (m²)
• The flux linkage ΦN has the units of?Weber turns?(Wb turns)
• As with magnetic flux, if the field lines are not completely perpendicular to the plane of the area they are passing through
• Therefore, the component of the flux density which is perpendicular is equal to:

ΦN = BAN cos(θ)

Step 1:?Write out the known quantities

Cross-sectional area, A = πr²?= π(0.4)²?= 0.503 m²

Magnetic flux density, B = 5.1 mT

Number of turns of the coil, N = 300 turns

Step 2:?Write down the equation for the magnetic flux linkage

ΦN = BAN

Step 3:?Substitute in values and calculate

ΦN = (5.1 × 10^-3) × 0.503 × 300 = 0.7691 = 0.8 Wb turns (2 s.f)