?W = m?V


Gravitational potential energy increases as a satellite leaves the surface of the Moon

A spacecraft of mass 300 kg leaves the surface of Mars to an altitude of 700 km.Calculate the work done by the spacecraft.Radius of Mars = 3400 km
Mass of Mars = 6.40 × 1023?kg
Step 1:??????????? Write down the work done (or change in G.P.E) equation

Step 2:??????????? Determine values for r1?and r2
r1?is the radius of Mars = 3400 km = 3400 × 103?m
r2?is the radius + altitude = 3400 + 700 = 4100 km = 4100 × 103?m
Step 3: ?????????? Substitute in values

ΔG.P.E =? 643.076 × 106??=?640 MJ (2 s.f.)
Make sure to not confuse the ΔG.P.E equation with
ΔG.P.E = mgΔh
The above equation is only relevant for an object lifted in a uniform gravitational field (close to the Earth’s surface).The new equation for G.P.E will not include?g, because this varies for different planets and is no longer a constant (decreases by 1/r2) outside the surface of a planet.


Gravitational equipotential lines in a non-uniform and uniform gravitational field
Remember equipotential lines?should not?have arrows on them like gravitational field lines do, since they have no particular direction and are not vectors.Make sure to draw any straight lines with a ruler or a straight edge.
轉載自savemyexams
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